Once the circuit was constructed, it was apparent that the circuit contains a feedback loop. By putting a resistor in between the output voltage and the input voltage, the operation amplifier can be made to output the desired voltage gain.
The circuit was then connected to two separate voltage sources providing various voltages starting from 0 and ending in 1. We went in 0.25 volt increments. The following is
Vin | Vout | GAIN | Vri | Iri | Vrf |
0 | 0 | 0 | 0 | 0 | 0 |
0.25 | -2.39 | 9.958 | 0.24 | 0.235 | 2.39 |
0.5 | -4.9 | 9.8 | 0.5 | 0.504 | 4.9 |
0.75 | -7.44 | 9.92 | 0.75 | 0.707 | 7.43 |
1 | -9.93 | 9.83 | 1.01 | 1 | 9.93 |
It came out that the current being drawn from sources were about 7.5 and 1.8 milliamps. These were not expected but that may be in part due to the fact that the power supplies (voltage supplies) were also being used to power the voltage dividers.
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